
Probability: mutually exclusive events | Math Help Forum
Oct 1, 2008 · Hi! So i don't know why but i am totally bugging on this problem: "An experiment results in one of three mutually exclusive events A,B and C. It is knows that p(A)=.30, p(B)=.55 …
Probability with mutually exclusive events | Math Help Forum
Oct 13, 2010 · Let A and B be the mutually exclusive events of S. Prove that in independent trials of this experiment, the even A occurs before the event B with probability P (A) / [P (A) + P (B)].
Mutually Exclusive - Math Help Forum
May 20, 2022 · Ahhh this is easy now. I think that the two events are mutually exclusive because they don't share the same outcome. And I think that since event A or event B doesn't include …
stat question - Math Help Forum
Feb 28, 2009 · An oil exploration company currently has two active projects, one in Asia and theother in Europe. Let A be the event that the Asian project is successful and B be the …
[SOLVED] Finding P (AandB)= and P (A)= | Math Help Forum
Feb 28, 2010 · The textbook mentions things such as "events are independent" "mutually exclusive" and "any events," which confuses me.. So I was just wondering which formula i'm …
Probability | Math Help Forum
Jul 30, 2008 · Assume you have applied for two scholarships, a Merit scholarship (M) and an Athletic scholarship (A) The probability that you receive an Athletic scholarship is 0.18. The …
Probability Spinner Question? - Math Help Forum
Jan 2, 2010 · Each of the five spinners are mutually exclusive events (no two can occur at the same time). Therefore the probability of an even on one spin is simply the sum of the …
Probability. Not for the faint of heart - Math Help Forum
Feb 3, 2009 · Let S be a given set. If, for some k>0, S1,S2,....Sk are mutually exclusive nonempty subsets of S such that union (i=1 to k) Si=S, , then we call the set {S1,S2,…,Sk} a partition of …
SOLVED - Probability question | Math Help Forum
Oct 13, 2010 · An actuary studying the insurance preferences of automobile owners makes the following conclusions: An automobile owner is twice as likely to purchase collision coverage as …
[SOLVED] Mutually independent - Math Help Forum
Feb 2, 2009 · Problem: Let the three mutually independent events C 1, C 2, C 3, be such that P (C 1) = P (C 2) = P (C 3) = 1 4 . Find P [(C 1 c ∩ C 2 c) ∪ C 3] . Attempt: By the definition of …